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 Find at least 3 solutions for the following linear equation in two variables:

2x + 5y = 13


2x + 5y = 13

rightwards double arrow      5y = 13 - 2x 

rightwards double arrow       straight y equals fraction numerator 13 minus 2 straight x over denominator 5 end fraction
Put x = 0, then  straight y equals fraction numerator 13 minus 2 left parenthesis 0 right parenthesis over denominator 5 end fraction equals 13 over 5

Put x = 1, then y equals fraction numerator 13 minus 2 left parenthesis 1 right parenthesis over denominator 5 end fraction equals 11 over 5

Put x = 2, then straight y equals fraction numerator 13 minus 2 left parenthesis 2 right parenthesis over denominator 5 end fraction equals 9 over 5

Put x = 3, then straight y equals fraction numerator 13 minus 2 left parenthesis 3 right parenthesis over denominator 5 end fraction equals 7 over 5

therefore space space space open parentheses 0 comma space 13 over 5 close parentheses comma space open parentheses 1 comma space 11 over 5 close parentheses comma space open parentheses 2 comma space 9 over 5 close parentheses space a n d space space open parentheses 3 comma space 7 over 5 close parentheses are the solutions of equation  2x + 5y = 13.

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Write each of the following equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
(i) 2x + 3y = 4.37             
(ii) x - 4 = square root of 3 space y
(iii) 4 = 5x - 3y
(iv) 2x = y

Solution not provided.

Ans.    (i) 2X + 3Y - 4.37 = 0; a = 2,   b = 3 and   c = - 4.37
          (ii) x - square root of 3 y - 4 = 0; s = 1, b = negative square root of 3 comma space c = -4
          (iii) - 5x + 3y + 4 = 0; a = -5,  b = 3 and c  = 4
                                or 
                   5x - 3y - 4 = 0; a = 5, b = 3 and c = -4
          (iv) 2x - y + 0 = 0; a = 2,  b = -1 and c = 0

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Find solutions of the form x = a, y = 0 and x = 0, y = b for the following pairs of equations. Do they have any common such solution?

3x + 2y = 6 and 5x + 2y = 10


                                  3x + 2y = 6
Put y = 0,  we get      3x + 2(0) = 6
rightwards double arrow                                     3x = 6

rightwards double arrow                               straight x equals 6 over 3 equals 2
therefore space space space space space space space    (0, 3) is a solution

                                    5x + 2y = 10
Put y = 0, we get         5x + 2(0) = 10

rightwards double arrow                                       5x = 10

rightwards double arrow                                 straight y space equals 10 over 2 equals 5
therefore    (0, 5) is a solution.

The given equations have a common solution (2, 0)

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Express the linear equation 7 = 2x in the form ax + by + c = 0 and also write the values of a, b and c

7 = 2x
⇒ 2x – 7 = 0
⇒ 2x + 0y – 7 = 0
Comparing with ax + by + c = 0, we get
a = 2
b = 0
c = –7

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Write each of the following as an equation in two variables:

(i) x = – 5 (ii) y = 2

(iii) 2x = 3 (iv) 5y = 2.


Solution not provided.

Ans.    (i) 1 x + 0y + 5 = 0               
          (ii) 0x + 1y - 2 = 0
         (iii) 2x + 0y - 3 = 0
         (iv) 0x + 5y - 2 = 0
         

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